Johnny SolidWorks
Hot Rolled
- Joined
- Apr 2, 2013
- Location
- Rochester
Hey Gang - I know it's kind of a weird question, but if we could keep this thread from turning into a "well why would you need to know that?" dogpile, it would be appreciated. And yes, I understand by saying that, at least one person will feel the need to comment exactly that, so 'thank you' for that ahead of time.
I'm looking for help figuring out the cutting forces (the resolved forces in X, Y, and Z) for a chamfering OP.
Let's say, for the sake of this discussion, I want to put a .010" chamfer on a square edge. The effective area of the cut (area of a triangle) is 0.00005 in^2, and let's say I want to do it quickly, at 800 ipm. That gives me a MRR of 0.04 in^3/min, in tool steel with a K factor of 1.56.
So my HP Consumption is 0.025 (or effectively nothing.)
And this is where my understanding falls flat. Assuming this is an infinitely long straight line, how do I figure out the resolved forces in X, Y, and Z directions? Cutter geometry should impact this significantly, correct? But if I were to assume some sort of mythical cutter that put all of the cutting force along just one axis, how much force would it be? If I'm using a 4 flute tool versus a 1 flute tool (like a PCD ball endmill), the cutting force isn't impacted at the same feeds and speeds, correct? If I'm using a carbide burr tool that doesn't have a specified flute count, is the cutting force the same/similar?
Thanks for the help!
I'm looking for help figuring out the cutting forces (the resolved forces in X, Y, and Z) for a chamfering OP.
Let's say, for the sake of this discussion, I want to put a .010" chamfer on a square edge. The effective area of the cut (area of a triangle) is 0.00005 in^2, and let's say I want to do it quickly, at 800 ipm. That gives me a MRR of 0.04 in^3/min, in tool steel with a K factor of 1.56.
So my HP Consumption is 0.025 (or effectively nothing.)
And this is where my understanding falls flat. Assuming this is an infinitely long straight line, how do I figure out the resolved forces in X, Y, and Z directions? Cutter geometry should impact this significantly, correct? But if I were to assume some sort of mythical cutter that put all of the cutting force along just one axis, how much force would it be? If I'm using a 4 flute tool versus a 1 flute tool (like a PCD ball endmill), the cutting force isn't impacted at the same feeds and speeds, correct? If I'm using a carbide burr tool that doesn't have a specified flute count, is the cutting force the same/similar?
Thanks for the help!