I'm plugging a hole drilled off-center. I know the old adage: "A bad craftsman blames his tools", and as a general rule, I agree with that. However, when you buy a jig, you expect it to be true. The final responsibility falls to the machinist to make sure the jig is true, and I accept that responsibility in this matter. Nonetheless, I have to fix a hole that is 0.010" off center. It is my intent to use an interference fit to plug the hole.
The hole is 0.694" in diameter. There will be essentially no stress on the repair. I intend to use "green" Locktite as well as the interference fit to hold the plug in place as I drill and ream the new hole on center. Both pieces of aluminum are 6061.
Here are my questions,(and I have looked in the archives. I found no threads or posts on AL-to-AL interference fits, but then I may have missed one):
1) Can the difference between the 'sleeve' and plug be as large as 0.002" IF the sleeve is heated and the plug cooled?
2) If not, given the 0.694" ID of the 'sleeve', what is the largest plug OD can I get away with without using a press? (The "sleeve" is a relatively complex form as well as not particularly 'sturdy', so it doesn't lend itself to being held under a press without a LOT of fiddling. I COULD do it, but I don't want to unless I absolutely HAVE to.) I expect the Loctite to provide SOME, but minimal, lubrication.
Thanks,
Paul
PS - I see that Aluminum has an average coefficient of thermal expansion of ~0.0000125"/degree(F). If I need to have 0.002" of ID-OD difference, then it would appear to me that I need a temperature differential of no less than 160 degrees F.
0.002/0.0000125 = 160
Can someone:
1) Verify this (not mathematically, but practically), and
2) Does this "sound about right" to those that have done something like this?
Thanks,
Paul
The hole is 0.694" in diameter. There will be essentially no stress on the repair. I intend to use "green" Locktite as well as the interference fit to hold the plug in place as I drill and ream the new hole on center. Both pieces of aluminum are 6061.
Here are my questions,(and I have looked in the archives. I found no threads or posts on AL-to-AL interference fits, but then I may have missed one):
1) Can the difference between the 'sleeve' and plug be as large as 0.002" IF the sleeve is heated and the plug cooled?
2) If not, given the 0.694" ID of the 'sleeve', what is the largest plug OD can I get away with without using a press? (The "sleeve" is a relatively complex form as well as not particularly 'sturdy', so it doesn't lend itself to being held under a press without a LOT of fiddling. I COULD do it, but I don't want to unless I absolutely HAVE to.) I expect the Loctite to provide SOME, but minimal, lubrication.
Thanks,
Paul
PS - I see that Aluminum has an average coefficient of thermal expansion of ~0.0000125"/degree(F). If I need to have 0.002" of ID-OD difference, then it would appear to me that I need a temperature differential of no less than 160 degrees F.
0.002/0.0000125 = 160
Can someone:
1) Verify this (not mathematically, but practically), and
2) Does this "sound about right" to those that have done something like this?
Thanks,
Paul
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