Evan
Titanium
- Joined
- Jan 29, 2004
- Location
- Williams Lake, BC, Canada
It's a hobby these days Bob. I used to do it for a living. I take as much time as I please.
Incidentally, if you make a bimetal strip as I suggested it is amazing how a tiny bit of differential expansion creates a HUGE bend. A iron lathe on an aluminum plate would be a sort of bimetal strip. A differential change of .005 could bend things by maybe .1" over three feet. The force would be in the tons.
Specifically, the yield strength for 6061 T6 is around 40,000lbs per sq". If I put my SB on a plate 1/2 by 8 by 3' that would give a cross sectional area of 4 sq". The force generated by expansion or contraction would be in the area of 160,000lbs or 80 tons. Should be enough to bend any lathe. The amount of bend can also be calculated but I don't have my scientific calculator handy. It would be the tangent of the angle created by the difference in length over the distance from the plate to the bed / plate length.
[This message has been edited by Evan (edited 03-06-2004).]
Incidentally, if you make a bimetal strip as I suggested it is amazing how a tiny bit of differential expansion creates a HUGE bend. A iron lathe on an aluminum plate would be a sort of bimetal strip. A differential change of .005 could bend things by maybe .1" over three feet. The force would be in the tons.
Specifically, the yield strength for 6061 T6 is around 40,000lbs per sq". If I put my SB on a plate 1/2 by 8 by 3' that would give a cross sectional area of 4 sq". The force generated by expansion or contraction would be in the area of 160,000lbs or 80 tons. Should be enough to bend any lathe. The amount of bend can also be calculated but I don't have my scientific calculator handy. It would be the tangent of the angle created by the difference in length over the distance from the plate to the bed / plate length.
[This message has been edited by Evan (edited 03-06-2004).]