Good afternoon guys and gals.
So my question pertains to a G0554 lathe I purchased which has been crashed but it has only damaged the apron pinion shaft that rides on the rack gear. I am missing the shaft in its entirety so I will be making it, if and only if I can determine the proper splines on the pinion shaft! For the life of me I cant seem to come up with a proper number of teeth. The shaft with the handwheel on it has a 13t gear which then drives a 50t gear connected on the same shaft as the pinion gear which drives the M2 (2 module) rack. The divisions on my hand wheel have .005" per division, and a total of .58" per rotation. The metric readings show 14.6mm per rotation. The problem I have is that I'm coming up with like 9.5 teeth which is unreasonable, espe ially considering there would be a hell of alot of undercut. Usually ive been seeing like 13 or 14 teeth min on any diagram of a lathe pinion. Is there anyone here that can explain where my math is wrong? Or why Grizzlys numbers are wrong? If anyone could count the gear teeth on their pinion gear that would be extremely beneficial and I'd truly appreciate it!
The rack gear TPI ive come up with is 4.0416.. I measured a whole 12 inches and got 48.5. So 48.5/12 = 4.0416. Which means for the saddle to travel .58" id need to move
2.344 teeth on the rack gear. If one rotation of the handwheel rotates a 13t gear driving a 50t gear, that is .26 rotations of the driven shaft for every 1 rotation of the handwheel (13/50 = .26). I'm then solving for "P" number of pinion teeth. P x .26 = 2.344. Which is P = 2.344/.26. P = 9.01. Is this logical? Thanks in advance!
Regards,
Sean
So my question pertains to a G0554 lathe I purchased which has been crashed but it has only damaged the apron pinion shaft that rides on the rack gear. I am missing the shaft in its entirety so I will be making it, if and only if I can determine the proper splines on the pinion shaft! For the life of me I cant seem to come up with a proper number of teeth. The shaft with the handwheel on it has a 13t gear which then drives a 50t gear connected on the same shaft as the pinion gear which drives the M2 (2 module) rack. The divisions on my hand wheel have .005" per division, and a total of .58" per rotation. The metric readings show 14.6mm per rotation. The problem I have is that I'm coming up with like 9.5 teeth which is unreasonable, espe ially considering there would be a hell of alot of undercut. Usually ive been seeing like 13 or 14 teeth min on any diagram of a lathe pinion. Is there anyone here that can explain where my math is wrong? Or why Grizzlys numbers are wrong? If anyone could count the gear teeth on their pinion gear that would be extremely beneficial and I'd truly appreciate it!
The rack gear TPI ive come up with is 4.0416.. I measured a whole 12 inches and got 48.5. So 48.5/12 = 4.0416. Which means for the saddle to travel .58" id need to move
2.344 teeth on the rack gear. If one rotation of the handwheel rotates a 13t gear driving a 50t gear, that is .26 rotations of the driven shaft for every 1 rotation of the handwheel (13/50 = .26). I'm then solving for "P" number of pinion teeth. P x .26 = 2.344. Which is P = 2.344/.26. P = 9.01. Is this logical? Thanks in advance!
Regards,
Sean