Hellow Everyone. I have developed the constant for the division in a gearhobber. Take a look to the attached file and tell me what u think.
I also want to develope the differential constant. But its a big challenge....
I accept help from everyone who wants sharing information about this old goodies machines 
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The cinematism of the Muir 4000 are attached in the picture were:
Division Constant = 180 (1nw worm with 240z table)
k=180
z= number or theets desired
k/z= a/b*c/d
Ok, We have just analize the division formula but where did it came from? Well take a look at the cinematism planes. and try to analize the machine in 3 different ways. the first will be:
TG(Table Gears) were ratio is:
960:1 = 20/5*240/1
second will be with the tg(Transposition Gears) were the ratio reffers to:
.5333333333= 32/60
and the third will be the HG(Hob Gears) were ratio is:
10:1 = 20/5*55/22
Finally!!! I have done this formula to calulate the constant:
K=TG / (tg x HG) 180= 960/ (.533333 * 10)
I hope u reply this thread. And hopping u help me to develope the differential formula
I also want to develope the differential constant. But its a big challenge....
I accept help from everyone who wants sharing information about this old goodies machines .The cinematism of the Muir 4000 are attached in the picture were:
Division Constant = 180 (1nw worm with 240z table)
k=180
z= number or theets desired
k/z= a/b*c/d
Ok, We have just analize the division formula
but where did it came from? Well take a look at the cinematism planes. and try to analize the machine in 3 different ways. the first will be:TG(Table Gears) were ratio is:
960:1 = 20/5*240/1
second will be with the tg(Transposition Gears) were the ratio reffers to:
.5333333333= 32/60
and the third will be the HG(Hob Gears) were ratio is:
10:1 = 20/5*55/22
Finally!!! I have done this formula to calulate the constant:
K=TG / (tg x HG) 180= 960/ (.533333 * 10)
I hope u reply this thread. And hopping u help me to develope the differential formula
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