Hydraulic Pressure Information

imachine909 · Mar 21, 2020

The picture below is of a what I have built to clamp some parts. Looking for information on how to calculate the foot pounds of clamping pressure. I am currently trying to find the correct hydraulic pump and valves to open and close the system. So my question is if I have say 100psi coming from the pump how do I figure out how many foot pounds of pressure will be on the part?

Vancbiker · Mar 21, 2020

Not enough information to get an answer. What piston size on your cylinder? Also the force exerted will just be pounds, not foot pounds which is a way of measuring torque.

imachine909 · Mar 21, 2020

The piston diameter is .788 inches. What else would be needed? Do you have formula?

welderboyjk · Mar 21, 2020

Area=pi*r^2
A .788 diameter piston should put you about .487 in^2
That means 100 psi should put you about 48.7 pounds of force on the piston. Minus seal friction n stuff.
Hope those machining loads are light!

imachine909 · Mar 21, 2020

So In a 6 inch Kurt vise we use a torque wrench set to 38 foot pounds. What would be the equivalent here?

welderboyjk · Mar 21, 2020

Kurt has a listing of clamping force of their current vises on their website.
A quick WAG would put you needed pressure somewhere north of 7k.

imachine909 · Mar 21, 2020

Awesome thank for the help!

Djstorm100 · Mar 21, 2020

You can add a adjustable prv to dial down pressure or up or use a vfd on the motor

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