I need to cut some straight gear teeth in a shaft...and my experience with the math behind this is zero.
The Voest drill is missing the pinion shaft used to crank the horizontal ram. See read arrow in pic. The teeth are about 2.5" long.
I read up on a few sites, including McMaster Carr, and I find myself getting more confused.
The shaft is 28mm (about 1.100") diameter. The rack teeth appear to be 4 teeth per inch (though this does not equate to any round MM value). From the top of the tooth to the bottom is about .140", give or take. The total angle is 60 degrees and the teeth don't look to have any visible curve or profile...they look to be a pretty straight-sided "V", or very close to it.
The McMaster site says to determine pitch, I should divide the number of teeth by 2 then multiply by the shaft diameter. Since I have 3.45 inches of circumference, that indicates I need 13.82 teeth. Since the diameter of the shaft can be smaller, I assume I would want 13 teeth as a round number. So...13/2 = 6.5 x 1.1 = 7.15 which would round down to a 7 pitch. Is that right or?
The Voest drill is missing the pinion shaft used to crank the horizontal ram. See read arrow in pic. The teeth are about 2.5" long.
I read up on a few sites, including McMaster Carr, and I find myself getting more confused.
The shaft is 28mm (about 1.100") diameter. The rack teeth appear to be 4 teeth per inch (though this does not equate to any round MM value). From the top of the tooth to the bottom is about .140", give or take. The total angle is 60 degrees and the teeth don't look to have any visible curve or profile...they look to be a pretty straight-sided "V", or very close to it.
The McMaster site says to determine pitch, I should divide the number of teeth by 2 then multiply by the shaft diameter. Since I have 3.45 inches of circumference, that indicates I need 13.82 teeth. Since the diameter of the shaft can be smaller, I assume I would want 13 teeth as a round number. So...13/2 = 6.5 x 1.1 = 7.15 which would round down to a 7 pitch. Is that right or?