Woodruff type key slot problem Error 367

Hi All,

I am attempting to mill a simple key in the side of a shaft. Its woodruff like in that it has radii at the start and end and a flat on the bottom but dimensionally its not a woodruff. The shaft diameter is 1.9375 and I have zero at the left end of the bar, front edge and top edge I am cutting a key that is .287 deep starting .0625 from the end with a 1.125 radius at the start end. The flat across the bottom is 2" long and it ends with the same 1.125 radius. The error I get is the 367 cutter interference error but the radius I need to mill is 1.125 and the cutter is a 2" diameter so I should be ok? If I drop the cutter diameter in the offsets to 1" it works. Any thoughts? 2009 Haas VF7

Thanks Nathan

%
o07757
T02M6
(2 inch side cutter .25 thick)
G90G54G00X2.00Y-5.000
S200M3
G43H02Z-.7187M8
G42G01X0.0625Y-2.00D02F2.0
G1Y0.00
G2X.8131Y.287R1.125
G1X2.8131
G2X3.5637Y0.00R1.125
G1Y-2.00
G1X2.00Y-5.00
G1Z-1.21875
G1X.0625Y0.00
G2X.8131Y.287R1.125
G1X2.8131
G2X3.5637Y0.00R1.125
G1Y-4.00
G40X2.00Y-5.00
G00Z2.00M9
G53G49Z0M5
M30
%

your geometry is a little strange. Did you program this by hand?

the arc moves only give you ~.7" of distance in X (and .287 in Y) when uncompensated, meaning the arc disappears completely with a tool diameter greater than 1.5 With a tool diameter of ~1.5 you can get past the first error and get another cutter comp interference alarm when you come back around and make the second pass.

Yes, by hand. Looks like some of your figures are different than mine. I'll revisit the numbers again. Am I right in thinking I should be able to interpolate a 1.125 radius with a 2.00 diameter side milling cutter? Sure seems like it.