CoveredInBees
Plastic
- Joined
- May 31, 2020
I'll make a longer story short:
I'm currently trying to size an inverter and batteries for an air compressor motor.
Here is the information from the Motor's Nameplate:
GE Motors
AIR COMPRESSOR MOTOR
MODEL: 5KCR48SR396U
PART NO.: 9035
VOLTS: 115/230
AMPS: 18.0/9.0
RPM: 3400
HP: 2.0
1 PHASE
PC: B1024
CODE: F
SERVICE FACTOR: 1
56-FRAME
So here is my question, the nameplate mentions that the motor's code is letter F, is that the NEMA nameplate rating?
Anyway here is my attempt at figuring this all out.
INRUSH = (5.59 'Code F' * 2HP * 1000) / 120 Volts = 93.2 Amps
93.2 AMPS * 120 Volts = 11,180 WATTS, but lets round that to 12,000 WATTS
Does that really mean I need a 12KVA Inverter just to get the motor started.
I do have a 1800 Running / 3600 Peak Dewalt Inverter, should I even bother trying it on that, or is that a little too under-powered?
I'm currently trying to size an inverter and batteries for an air compressor motor.
Here is the information from the Motor's Nameplate:
GE Motors
AIR COMPRESSOR MOTOR
MODEL: 5KCR48SR396U
PART NO.: 9035
VOLTS: 115/230
AMPS: 18.0/9.0
RPM: 3400
HP: 2.0
1 PHASE
PC: B1024
CODE: F
SERVICE FACTOR: 1
56-FRAME
So here is my question, the nameplate mentions that the motor's code is letter F, is that the NEMA nameplate rating?
Anyway here is my attempt at figuring this all out.
INRUSH = (5.59 'Code F' * 2HP * 1000) / 120 Volts = 93.2 Amps
93.2 AMPS * 120 Volts = 11,180 WATTS, but lets round that to 12,000 WATTS
Does that really mean I need a 12KVA Inverter just to get the motor started.
I do have a 1800 Running / 3600 Peak Dewalt Inverter, should I even bother trying it on that, or is that a little too under-powered?