Hello. I'm new here, first post.
I have an old 36" L Power & Co bandsaw I'm trying to get up and running again. it has wooden rimmed wheels with metal spokes. When I bought the saw years ago the motor was 3 hp 1750 rpm. The sheave on the motor was 3.5" outside diameter and the sheave on the driveshaft of the saw is 15.5". I believe this means the 36" wheel is turning about 395 rpm or less.
That motor has been repurposed over the years and I have a 7.5 hp 3 phase motor which runs at 3500 rpm I'd like to use on the saw. I'm trying to determine the sheaves I will need to reduce the 36" wheel to 300 - 350 rpm.
So my real question is, can someone tell me what diameter of the sheave I should be measuring for doing the calculations? From what I can tell, it seems as though the pitch diameter is the relevant number.
Thanks in advance for any help!
Pete
I have an old 36" L Power & Co bandsaw I'm trying to get up and running again. it has wooden rimmed wheels with metal spokes. When I bought the saw years ago the motor was 3 hp 1750 rpm. The sheave on the motor was 3.5" outside diameter and the sheave on the driveshaft of the saw is 15.5". I believe this means the 36" wheel is turning about 395 rpm or less.
That motor has been repurposed over the years and I have a 7.5 hp 3 phase motor which runs at 3500 rpm I'd like to use on the saw. I'm trying to determine the sheaves I will need to reduce the 36" wheel to 300 - 350 rpm.
So my real question is, can someone tell me what diameter of the sheave I should be measuring for doing the calculations? From what I can tell, it seems as though the pitch diameter is the relevant number.
Thanks in advance for any help!
Pete